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50a^2-60a+18=0
a = 50; b = -60; c = +18;
Δ = b2-4ac
Δ = -602-4·50·18
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{60}{100}=3/5$
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